3x^2+3x-108=0

Solution for 3x^2+3x-108=0 equation:

3x^2+3x-108=0

a = 3; b = 3; c = -108;
Δ = b2-4ac
Δ = 32-4·3·(-108)
Δ = 1305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1305}=\sqrt{9*145}=\sqrt{9}*\sqrt{145}=3\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{145}}{2*3}=\frac{-3-3\sqrt{145}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{145}}{2*3}=\frac{-3+3\sqrt{145}}{6}
$